Is the result zero-extended?
No. Bit 31 of the low 32-bit result is copied to bits 63..32: 0x80000000 becomes 0xffffffff80000000.
Add lower 32 bits of rs1 and rs2, producing 32-bit result sign-extended to 64 bits
ADDW (R-type, opcode=0111011, funct7=0000000, funct3=000) adds the lower 32 bits of rs1 and rs2, ignores overflow, sign-extends the 32-bit result to 64 bits, and writes it to rd. Unlike ADD in RV64I (a full 64-bit operation), ADDW operates only on the lower 32 bits and sign-extends.
RV64I; XLEN=64; 32-bit result → sign extension
addw rd, rs1, rs2Assume successful instruction fetch, no asynchronous interrupt or extra extension checks; one initial value per register.
0x00C5853BDecode the current instruction fields and read sources before writeback; no result has been committed.
These are teaching steps for architectural effects, not processor pipeline stages or cycles.
Add lower 32 bits of rs1 and rs2, producing 32-bit result sign-extended to 64 bits
RV64I, x11=0x7fffffff and x12=1: addw x10, x11, x12 yields 0xffffffff80000000.
RV64I, x11=0x7fffffff and x12=1: addw x10, x11, x12 yields 0xffffffff80000000.
No. Bit 31 of the low 32-bit result is copied to bits 63..32: 0x80000000 becomes 0xffffffff80000000.