Why does c.subw have register restrictions?
Many C formats encode registers with shorter fields, so some forms can access only x8..x15 or fixed registers.
RV64C 16-bit CA subtraction: sign-extend the low 32 bits of rd'-rs2' to 64 bits and write rd'.
RV64 C 2.0/Zca; 16-bit CA format, funct6=100111, funct2=00, op=01.
The three-bit rd'/rs1' and rs2' fields 000–111 select x8–x15; rd' is both an old-value source and the destination.
Take the low 32 bits of old x[rd']−old x[rs2'], then sign-extend bit31 to 64 bits and write rd'; identical sources share one old value. This encoding is reserved in RV32.
c.subw is an RV64C CA-format instruction. It subtracts rs2' from rd' as a 32-bit value, sign-extends bit 31 to XLEN, and writes rd'.
Shows only manual-defined compressed fields, operands, and architectural state; it does not model a pipeline, cache, or timing.
rd'/rs1'=000 -> x8; rs2'=001 -> x9
c.subw is an RV64C CA-format instruction. It subtracts rs2' from rd' as a 32-bit value, sign-extends bit 31 to XLEN, and writes rd'.
RV64 C/Zca, old x8=0 and x9=1: c.subw x8, x9 has low 32-bit difference 0xffffffff and writes sign-extended x8=0xffffffffffffffff.
Many C formats encode registers with shorter fields, so some forms can access only x8..x15 or fixed registers.
No. It is a 16-bit encoded instruction defined by the C extension.