Is rs1 in FLW an FP register?
No. rs1 is an integer register that provides the memory base address; rd is the FP destination register.
Load a 32-bit single-precision floating-point value from memory into an f register.
FLW uses the I-type LOAD-FP encoding to load a 32-bit single-precision floating-point bit pattern from the effective address x[rs1] plus a signed 12-bit byte offset into floating-point register f[rd]. The transfer does not modify the bit pattern or canonicalize NaN payloads; when FLEN is greater than 32, the single-precision value is stored using NaN-boxing. Atomicity of naturally aligned access follows the official F-extension rule, while misaligned access is constrained by the execution environment.
Shows the F-extension FP load flow: decode the I-type encoding, form the address from an integer base plus a 12-bit offset, and transfer a 32-bit FP bit pattern.
The word is split as a I-type instruction; FP memory access is not an OP-FP arithmetic encoding.
FLW writes a 32-bit single-precision value to an FP register; RV64/FLEN>32 environments involve NaN-boxing. The transfer itself does not modify NaN payloads.
This animation shows only F-extension FP load/store ISA-visible address calculation and bit-pattern transfer; it does not model caches, buses, trap handlers, FPU pipelines, or microarchitectural timing.
FLW is the F-extension single-precision floating-point load. It forms the address from integer register rs1 plus a signed 12-bit byte offset, then loads a 32-bit bit pattern into FP register rd; this transfer is not FP arithmetic and does not use rm rounding.
Understand this scenario with real code like «flw f0, 0(x10)».
No. rs1 is an integer register that provides the memory base address; rd is the FP destination register.
No. FLW is a bit-pattern load, not an FP arithmetic operation; the transfer does not canonicalize NaN payloads.