Does ROR access memory?
No. This instruction reads its integer source registers and writes the computed result to rd; it performs no data-memory load or store.
Rotate right by register
Rotates rs1 right by the lower log2(XLEN) bits of rs2. Part of Zbb and Zbkb.
Starts with machine-code field decoding, then shows operand reads, instruction-specific execution, and ISA-visible state update.
Assumes Zbb or Zbkb is enabled at the selected XLEN, with the fixed register values below and PC=0x2000; fetch succeeds and no asynchronous interrupt occurs. Steps are a teaching decomposition.
The machine code is split by the current instruction format; the animation starts from encoding/decode.
This animation shows ISA-visible decode and state changes, not any specific CPU pipeline, cache, prediction, or timing implementation.
Rotate rs1 right by rs2[4:0] in RV32 or rs2[5:0] in RV64; bits leaving the low end wrap to the high end.
Understand this scenario with real code like «ror x10, x11, x12 ; x10 = rotr(x11, x12 & (XLEN-1))».
Understand this scenario with real code like «ror x10, x11, x12 ; x10 = rotr(x11, x12 & (XLEN-1))».
No. This instruction reads its integer source registers and writes the computed result to rd; it performs no data-memory load or store.
ROR rotates at the complete XLEN width and writes an equally wide result to rd: rs2[4:0] in RV32 and rs2[5:0] in RV64.