Is v0 an execution mask in VMSBC.VVM?
No. The corresponding v0 bit is borrow-in arithmetic input.
VMSBC computes each body element's borrow-out and writes the Boolean result to the destination mask register.
VMSBC.VVM computes vs2[i] - vs1[i] - v0.mask[i] from unsigned SEW source bit patterns for each body element. vd.mask[i] is 1 exactly when the difference before truncation is negative. Fixed vm=0 uses v0 as borrow-in, not an execution mask. Every body element executes; mask tails are always agnostic.
Starts from OP-V encoding fields, then shows how VMSBC uses each v0 bit as borrow-in and writes each borrow-out as a destination mask bit.
Require valid vtype, enabled VS, and supported SEW; VL=0 updates no destination, including tails. VMSBC writes one mask bit per body element; tails are always agnostic. With m1, vd may equal a data source or v0. With borrow-in, v0 cannot also be a SEW data source.
The teaching model fixes LMUL=m1 and vstart=0 and shows only body elements in the selected VL. It fixes VLEN=4096, VLMAX=4096/16=256, and assumes support for the selected SEW; equal vector sources require equal elements. In ordinary masked forms, inactive and tail elements follow vtype.vma/vta and the result row does not invent a definite value; VADC/VMADC/VSBC/VMSBC execute every body element, with v0 bits used only as carry/borrow-in.
vmsbc.vvm uses OP-V encoding. The animation places fixed fields, register fields, vm, and the vs1 field in one encoding strip.
This animation shows only ISA-visible relationships from the official V extension: OP-V field decode, active-element reads, SEW-width integer borrow-out generation, v0 carry/borrow input, and vd writeback. It does not model pipelines, caches, or timing.
VMSBC.VVM generates a borrow mask: vd.mask[i]=(unsigned(vs2[i])-unsigned(vs1[i])-v0.mask[i]<0).
Compute vs2[i]-vs1[i]-v0.mask[i] from unsigned SEW source bits; vd.mask[i]=1 exactly when the pre-truncation difference is negative. Fixed vm=0 uses v0 as borrow-in; every body element executes.
32-bit OP-V: opcode=1010111, funct6=010011, funct3=000. The destination is one mask register: bit i corresponds to element i, not an integer difference.
The mask destination may be v0. Different-EEW overlap must start at the source group's lowest register. With LMUL=m1, vd may equal a data source. With borrow-in, v0 cannot also supply SEW data.
Require V 1.0, valid vtype, enabled VS, and supported SEW. Body is vstart≤i<vl; prestart is unchanged. Every body element writes a mask bit; mask tails are always agnostic. vl=0 or vstart≥vl updates no destination, including tails. The animation fixes m1, VLEN=4096, and vstart=0; steps are not processor cycles.
Assume RV32/RV64 V 1.0, enabled VS, valid e32,m1, VLEN≥128, vl=4, vstart=0, ta/ma, and initialized sources; v2=[0,7,0xffffffff,4], v3=[1,7,0,3], v0.mask=[0,1,0,1] → v1.mask[0..3]=[1,1,0,0]. Only borrow bits are written; mask tails are always agnostic.
Assume RV32/RV64 V 1.0, enabled VS, valid e32,m1, VLEN≥128, vl=4, vstart=0, ta/ma, and initialized sources; v2=[0,7,0xffffffff,4], v3=[1,7,0,3], v0.mask=[0,1,0,1] → v1.mask[0..3]=[1,1,0,0]. Only borrow bits are written; mask tails are always agnostic.
No. The corresponding v0 bit is borrow-in arithmetic input.
It writes one destination mask bit for borrow-out.