Is v0 an ordinary execution mask here?
Here each v0 mask bit is the carry-in, not an element enable bit.
Add each vs2 element with scalar rs1 and carry-in from v0: vd[i]=vs2[i]+x[rs1]+v0.mask[i].
VADC.VXM performs vector-scalar add with carry: vd[i] = vs2[i] + x[rs1] + v0.mask[i]. The corresponding v0 mask bit is carry-in, not an element execution mask; VADC is encoded as a masked form but writes all body elements. Use VMADC to generate carry-out.
VADC.VXM is an RVV add-with-carry sum instruction for multi-word arithmetic. Carry-in comes from v0.mask[i], the sum is written to normal vector register vd, and carry-out must be generated separately with VMADC.
Understand this scenario with real code like «vsetvli t0, a0, e32, m1, ta, ma vmadc.vim v0, v8, 0 vadc.vxm v10, v8, a1, v0».
Understand this scenario with real code like «vsetvli t0, a0, e32, m1, ta, ma vmadc.vim v0, v8, 0 vadc.vxm v10, v8, a1, v0».
Here each v0 mask bit is the carry-in, not an element enable bit.
No. VADC writes the sum; VMADC produces the carry mask for the next step.