Check vl first
The current vl determines the number of body elements. Typical code executes vsetvli, vsetivli, or vsetvl before this instruction.
VMADC computes each body element's carry-out and writes the Boolean result to the destination mask register.
VMADC.VXM is the RISC-V V extension vector-scalar add carry-out instruction. It does not write a SEW-width integer result. For each body element within the current vl, it computes the carry-out of vs2 + the second source + v0[i] and writes one destination mask bit. v0 is carry-in arithmetic input, not an ordinary v0.t execution mask.
Starts from OP-V encoding fields, then shows how VMADC uses each v0 bit as carry-in and writes each carry-out as a destination mask bit.
vmadc.vxm uses OP-V encoding. The animation places fixed fields, register fields, vm, and the rs1 field in one encoding strip.
This animation shows only ISA-visible relationships from the official V extension: OP-V field decode, active-element reads, SEW-width integer carry-out generation, v0 carry/borrow input, and vd writeback. It does not model pipelines, caches, or timing.
VMADC generates carry bits for multiword addition: v0 supplies the input bit and vd.mask[i] stores the output bit.
When reading VMADC.VXM, do not stop at the mnemonic. Official V-extension semantics also depend on the current vl, vtype, and mask state. The suffix and operand form determine whether sources are vector, scalar, or immediate values.
The current vl determines the number of body elements. Typical code executes vsetvli, vsetivli, or vsetvl before this instruction.
The current vtype supplies SEW, LMUL, tail policy, and mask policy; these affect element width, register-group size, and inactive/tail destination elements.
For ordinary vector instructions with vm, vm=0 uses v0 as the execution mask and vm=1 is unmasked. A few forms such as VMERGE use v0 as data-selection input.
Understand this scenario with real code like «vmadc.vxm v1, v2, a1, v0».
Understand this scenario with real code like «vmadc.vxm v1, v2, a1, v0».
Understand this scenario with real code like «vmadc.vxm v1, v2, a1, v0».
No. The corresponding v0 bit is carry-in arithmetic input.
It writes one destination mask bit for carry-out.