Does VLE64.V automatically set vl?
No. vl/vtype are set by an earlier vsetvli, vsetivli, or vsetvl; vector loads and stores execute under the current configuration.
Load 64-bit elements into vd from x[rs1] with unit stride.
VLE64.V is a RISC-V V 64-bit unit-stride vector load. Active body elements read memory elements from consecutive addresses x[rs1] + i * 8 bytes and write vd; with vm=0, v0.t selects elements and masked-off elements do not access memory.
Decode the 64-bit unit-stride load, then compute each element address as x[rs1] + i * 8.
Teaching context: VLEN=4096, SEW=EEW=64, LMUL=EMUL=m1, VLMAX=64, vstart=0, valid vtype, enabled VS, and ta/ma. Base options are naturally aligned; rs1=x0 fixes the base at 0. Only the selected synchronous-fault scenario is modeled, assuming other selected memory is readable; actual system accessibility is not guaranteed. Per-element steps explain addresses and results, not access order or processor cycles. Inactive/tail elements may retain old values or become all ones; no definite result is shown. Normal completion resets vstart=0.
The animation starts from the 32-bit vector memory encoding and shows the official bit fields: nf, mew, mop, vm, rs2/vs2 or lumop/sumop, width, register fields, and opcode.
VLE64.V is an RVV 64-bit unit-stride vector load: each active element uses address x[rs1] + i * 8 bytes to read from memory, and element data is written into destination vector register group vd. vl and the v0.t mask decide which body elements actually access memory.
vd receives EEW=64-bit memory bit patterns; EMUL=(EEW/SEW)×LMUL must be in 1/8..8 with a legal register-group start. Elements are not extended into XLEN-wide scalars.
rs1 is an integer base register; element i uses x[rs1]+i×8 bytes, with base 0 for rs1=x0. v0.t gives vm=0; omitting it gives vm=1.
Require enabled V and valid vtype. Active body elements satisfy vstart≤i<vl and mask enabled; masked vd cannot cover v0. Disabled elements access no memory; inactive/tail follow vma/vta and prestart stays unchanged. VL=0 or vstart≥vl updates no destination.
This instruction executes under current vl without changing it; normal completion resets vstart=0. Misalignment may succeed or raise an address-misaligned exception; unit stride guarantees no element access order.
Assume enabled V/VS, valid e64,m1, VLMAX≥4, AVL=4, and vl=4, vstart=0, ta/ma after vsetvli; destination does not overlap source masks. Memory is readable except for the selected fault; address step=8 bytes: a0=0x8000, v0=[1,0,1,1], mem=[10,20,30,40] → vd=[10,agnostic,30,40]. Agnostic elements may retain old values or become all ones, without guaranteed zeros.
Assume enabled V/VS, valid e64,m1, VLMAX≥4, AVL=4, and vl=4, vstart=0, ta/ma after vsetvli; destination does not overlap source masks. Memory is readable except for the selected fault; address step=8 bytes: a0=0x8000, v0=[1,0,1,1], mem=[10,20,30,40] → vd=[10,agnostic,30,40]. Agnostic elements may retain old values or become all ones, without guaranteed zeros.
No. vl/vtype are set by an earlier vsetvli, vsetivli, or vsetvl; vector loads and stores execute under the current configuration.
Active element i uses x[rs1] + i * 8 bytes. This is contiguous memory access, not arbitrary gather/scatter.
No. With vm=0, a body element whose v0.t bit is 0 does not perform that element's load memory access.