Does vsetvli x0, x0 always set VLMAX?
No. rs1=x0 and rd=x0 preserves the existing vl; requesting VLMAX requires rd!=x0.
Set vtype and vl: rd receives new vl, rs1/rd encoding determines AVL, and vtypei selects SEW, LMUL, and tail/mask policy
VSETVLI uses opcode 1010111 (0x57), funct3 111. The rs1 field selects the source register, the 12-bit immediate provides the second operand, and rd selects the destination.
VSETVLI is an RVV configuration instruction: it determines AVL from the rs1/rd encoding, sets SEW, LMUL, vta, and vma from vtypei, and writes the new vl to rd. If rs1!=x0, AVL=x[rs1]; if rs1=x0 and rd!=x0, AVL=~0 to request VLMAX; if rs1=x0 and rd=x0, the current vl is used and the form is valid only when the new SEW/LMUL ratio does not change VLMAX.
VSETVLI derives AVL from the rs1/rd encoding, sets SEW, LMUL, and tail/mask policy from vtypei, then writes the selected new vl to rd. Modern assembly should spell out ta/tu and ma/mu.
Understand this scenario with real code like «vsetvli t0, a0, e32, m1, ta, ma # set vl for 32-bit elements».
Understand this scenario with real code like «vsetvli t0, a0, e32, m1, ta, ma # set vl for 32-bit elements».
Understand this scenario with real code like «vsetvli t0, a0, e32, m1, ta, ma # set vl for 32-bit elements».
No. rs1=x0 and rd=x0 preserves the existing vl; requesting VLMAX requires rd!=x0.
V 1.0 assembly syntax requires explicit tail and mask policy flags to avoid old-default ambiguity.